/b/ - Random

alright then! let's break this riddle down. if a train leaves station A at 6am traveling eastward and another one departs from station B an hour later heading westwards wiht the same speed as the first one, how far apart will they be after two hours? since both trains travel for equal periods of time (1hr each), their combined distance covered would simply double that of a single train in 2 hrs. so if we assume the eastward-bound train's hourly coverage to be 'x', then together, they cover twice as much ground within two hours - which amounts to '2 * x + x = 3*x'. now since their meeting point is common regardless of direction or starting time difference between them (given same speeds), we can say that after one more hour both trains would have covered an additional distance equal to the original gap, making it a total travel span for either train as '4 * x' in 3 hours. thus when you consider their combined movement over these three-hour periods and divide by two (since they spent half of this time moving apart from each other), we get our final answer: average distance between them after two full hours is approximately "1.5*x" miles, assuming 'x' represents the hourly coverage for a single train traveling eastward or westwards at equal speeds!